Changing a Bit in C Programing

I am coding in C programming.
Let's say I have a character:
char letter=0x0000;
So the binary data for the letter is now "00000000"
let say I want change the binary data to "10000000" and later to change it "10010000", is there a bitwise operator or method that would allow me to change a "0" to a "1" or "1" to a "0" at a specific position. Also is this possible?

You can use bitwise AND (&) and OR (|) operator.
For example:

01001000 |
10111000 =
11111000

This is done following:
72 | 184 = 248

(72 = 64+8)

For details see following tutorial:

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Yes it is very much possible. Just use bitwise exclusive OR or simply XOR operator on the number with 2 to the power of n where as n is the digit you want to change. ^ is the XOR operator in C.

000000 (decimal 0)
^ 100000 (decimal 32 = 2 power 5 = 1 << 5)
= 100000

1010 (decimal 10)
XOR 0010 (decimal 2 = 2 power 1 = 1 << 1)
= 1000

You can calculate 2 to the power of n by simply shifting bits in 1 by n bits. So 2 to the power of 4 can be obtained by shifting bits in 1 by 4 places.

inputNum ^ (1 << n) will give what you needed if toggling is all you need.

Bitwise XOR "^"
bit a bit b a ^ b (a XOR b)
0 0 0
0 1 1
1 0 1
1 1 0

However remember that doing XOR on a bit that already has 1 will convert it to zero. because 1 ^ 1 = 0;

If you just want to convert 0 to 1 and keep 1 if it is already there. You can have to use bitwise Or operator.

Bitwise OR "|"
bit a bit b a | b (a OR b)
0 0 0
0 1 1
1 0 1
1 1 1

Following is an example

11001110
| 10011000
= 11011110

Source:

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&

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If you XOR any bit with a 1 bit, it toggles its value:

0 ^ 1 = 1
1 ^ 1 = 0

Similarly, if you XOR any bit with 0, it keeps the same value:

0 ^ 0 = 0
1 ^ 0 = 1

Therefore, you can flip the nth bit of a number by XORing it with a number that has zero bits everywhere except in bit n:

val ^= (1 << n);

Hope this helps!