Get current URL/URI without some of $_GET variables

How, in Yii, to get the current page's URL. For example:

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but excluding the `$GET_['lg']` (without parsing the string manually)?

I mean, I'm looking for something similar to the `Yii::app()->requestUrl` / `Chtml::link()` methods, for returning URLs minus some of the `$_GET` variables.

**Edit**: Current solution:

unset $_GET['lg'];

echo Yii::app()->createUrl(
Yii::app()->controller->getId().'/'.Yii::app()->controller->getAction()->getId() ,
$_GET
);

I don't know about doing it in Yii, but you could just do this, and it should work anywhere (largely lifted from my answer [here](

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)):

// Get HTTP/HTTPS (the possible values for this vary from server to server)
$myUrl = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] && !in_array(strtolower($_SERVER['HTTPS']),array('off','no'))) ? 'https' : 'http';
// Get domain portion
$myUrl .= '://'.$_SERVER['HTTP_HOST'];
// Get path to script
$myUrl .= $_SERVER['REQUEST_URI'];
// Add path info, if any
if (!empty($_SERVER['PATH_INFO'])) $myUrl .= $_SERVER['PATH_INFO'];

$get = $_GET; // Create a copy of $_GET
unset($get['lg']); // Unset whatever you don't want
if (count($get)) { // Only add a query string if there's anything left
$myUrl .= '?'.http_build_query($get);
}

echo $myUrl;

Alternatively, you could pass the result of one of the Yii methods into [`parse_url()`](

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), and manipulate the result to re-build what you want.

Something like this should work, if run in the controller:

$controller = $this;
$path = '/path/to/app/'
. $controller->module->getId() // only necessary if you're using modules
. '/' . $controller->getId()
. '/' . $controller->getAction()->getId()
. '/';

This assumes that you are using 'friendly' URLs in your app config.

Yii::app()->createAbsoluteUrl(Yii::app()->request->url)

This will output something in the following format:

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Try to use this variant:

<?php echo Yii::app()->createAbsoluteUrl('your_yii_application/?lg=pl', array('id'=>$model->id));?>


It is the easiest way, I guess.

So, you may use

Yii::app()->getBaseUrl(true)


to get an Absolute webroot url, and strip the http[s]://

To get the absolute current request url (exactly as seen in the address bar, with GET params and http://) I found that the following works well:

Yii::app()->request->hostInfo . Yii::app()->request->url

$validar= Yii::app()->request->getParam('id');

You are definitely searching for this

Yii::app()->request->pathInfo

Most of the answers are wrong.

The Question is to get url without some query param .

Here is the function that works. It does more things actually. You can remove the param that you don't want and you can add or modify an existing one.

/**
* Function merges the query string values with the given array and returns the new URL
* @param string $route
* @param array $mergeQueryVars
* @param array $removeQueryVars
* @return string
*/
public static function getUpdatedUrl($route = '', $mergeQueryVars = [], $removeQueryVars = [])
{
$currentParams = $request = Yii::$app->request->getQueryParams();

foreach($mergeQueryVars as $key=> $value)
{
$currentParams[$key] = $value;
}

foreach($removeQueryVars as $queryVar)
{
unset($currentParams[$queryVar]);
}

$currentParams[0] = $route == '' ? Yii::$app->controller->getRoute() : $route;

return Yii::$app->urlManager->createUrl($currentParams);

}

usage:

ClassName:: getUpdatedUrl('',[],['remove_this1','remove_this2'])

This will remove query params 'remove_this1' and 'remove_this2' from URL and return you the new URL