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How to get correct current URL in JSP in Spring webapp

#11
Anyone who wants to know about other than the reuqest URI, for example a query string, you can check all the names of the variables in the code of [`RequestDispatcher`](

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Servlet API 3.1+) interface.

You can get the query string like this:

${requestScope['javax.servlet.forward.query_string']}
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#12
Here's an approached I've had success with to build an internal link (not absolute):

    Path:  `${requestScope['javax.servlet.forward.servlet_path']}`<br>
Params: `${requestScope['javax.servlet.forward.query_string']}`

Putting those together joined by `?` to construct the current url:

<c:set var="currentUrl" value="${requestScope['javax.servlet.forward.servlet_path']}?${requestScope['javax.servlet.forward.query_string']}"/>

Add additional url parameters as needed like:

<c:url value="${currentUrl}" var="enUrl"><c:param name="lang" value="en"/></c:url>
<c:url value="${currentUrl}" var="esUrl"><c:param name="lang" value="es"/></c:url>
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