How to reverse array in Swift without using ".reverse()"?

I like simple codes.

var names:[String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"]

var reversedNames = [""]

for name in names {
reversedNames.insert(name, at: 0)
}

print(reversedNames)

Do you really need a `for` loop? If not, you can use `reduce`.

I guess that this is the shortest way to achieve it without *reversed()* method (**Swift 3.0.1**):

["Apple", "Microsoft", "Sony", "Lenovo", "Asus"].reduce([],{ [$1] + $0 })

Here is @Abhinav 's answer translated to **Swift 2.2** :

var names: [String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"]

var reversedNames = [String]()

for arrayIndex in (names.count - 1).stride(through: 0, by: -1) {
reversedNames.append(names[arrayIndex])
}

Using this code shouldn't give you any errors or warnings about the use deprecated of C-style for-loops or the use of `--`.

**Swift 3 - Current:**

let names: [String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"]

var reversedNames = [String]()

for arrayIndex in stride(from: names.count - 1, through: 0, by: -1) {
reversedNames.append(names[arrayIndex])
}

Alternatively, you could loop through normally and subtract each time:

let names = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"]

let totalIndices = names.count - 1 // We get this value one time instead of once per iteration.

var reversedNames = [String]()

for arrayIndex in 0...totalIndices {
reversedNames.append(names[totalIndices - arrayIndex])
}

Here is the most simpler way.

let names:[String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"]

var reversedNames = [String]()

for name in names {
reversedNames.insert(name, at: 0)
}

Do it like this for reversed sorting.

let unsortedArray: [String] = ["X", "B", "M", "P", "Z"]
// reverse sorting
let reversedArray = unsortedArray.sorted() {$0 > $1}

print(reversedArray) // ["Z", "X", "P", "M", "B"]

You can use the swift3 document:

let names = ["Chris", "Alex", "Ewa", "Barry", "Daniella"]
let reversedNames = names.sorted(by: >)

// reversedNames is equal to:
// ["Ewa", "Daniella", "Chris", "Barry", "Alex"]

var rArray : [Int] = [2,5,6,8,3,8,9,10]
var ReArray = [Int]()
var a : Int = 1

func reversed (_ array: [Int]) -> [Int] {
for i in array {
ReArray.append(array[array.count-a])
a += 1
}

rArray = ReArray

return rArray
}

reversed(rArray)

print(rArray)

func reverse(array: inout [String]) {
if array.isEmpty { return }
var f = array.startIndex
var l = array.index(before: array.endIndex)
while f < l {
swap(array: &array, f, l)
array.formIndex(after: &f)
array.formIndex(before: &l)
}
}

private func swap( array: inout [String], _ i: Int, _ j: Int) {
guard i != j else { return }
let tmp = array[i]
array[i] = array[j]
array[j] = tmp
}

Or you can write extension of course

**Swift 3:**


var names:[String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"]

var reversedNames : [String] = Array(names.reversed())

print(reversedNames) // ["Asus", "Lenovo", "Sony", "Microsoft", "Apple"]

Here the code for swift 3



let array = ["IOS A", "IOS B", "IOS C"]
for item in array.reversed() {
print("Found \(item)")
}