Unable to swap values

In the below code, output remains same in both cases,thanks for pointing what am I missing:-

Before Swap:-
a=10 b=512
After Swap:-
a=10 b=512

Following is the code, It compiles and runs without any problem:-

#include <stdio.h>
int swap(int* x, int* y)
{
if(x != y)
{
_asm
{
mov eax,[x]; x into eax
mov ebx,[y]
mov [x],ebx;swapping now
mov [y],eax
}
}
return 0;
}

int main () {
int a=10,b=512;
printf("Before Swap:- \na=%d\t b=%d\n",a,b);
swap(&a,&b);
printf("After Swap:- \na=%d\t b=%d",a,b);//Value remains same
return 0;
}

No indirection on variables inside assembly block wont work.Instead take addresses in registers and then only try indirection.It will rather break into something like `mov eax, DWORD PTR _x$[ebp]`

#include <stdio.h>
int swap(int* x, int* y)
{
if(x != y)
{
_asm
{
mov eax,x
mov ebx,y
mov ecx,[ebx]
xchg ecx,[eax]
xchg [ebx],ecx
}
}
return 0;
}

int main () {
int a=10,b=512;
printf("Before Swap:- \na=%d\t b=%d\n",a,b);
swap(&a,&b);
printf("After Swap:- \na=%d\t b=%d",a,b);
getchar();
return 0;
}

You can swap with Xor operation -

void swap(int *x, int *y)
{
*x = *x ^ *y; /* #1 */
*y = *x ^ *y; /* #2 */
*x = *x ^ *y; /* #3 */
}