how to ignore whitespaces in fscanf()

I need to use `fscanf` to ignore all the white spaces and to not keep it.
I tried to use something like the combination between `(*)` and `[^\n]` as: `fscanf(file," %*[^\n]s",);`
Of course it crashed, is there any way to do it only with `fscanf`?

code:

int funct(char* name)
{
FILE* file = OpenFileToRead(name);
int count=0;
while(!feof(file))
{
fscanf(file," %[^\n]s");
count++;
}
fclose(file);
return count;
}


Solved !
change the original `fscanf()` to :
`fscanf(file," %*[^\n]s")`;
read all the line exactly as `fgets()` but didnt keep it!

Using a space (" ") in the fscanf format causes it to read and discard whitespace on the input until it finds a non-whitespace character, leaving that non-whitespace character on the input as the next character to be read. So you can do things like:

fscanf(file, " "); // skip whitespace
getc(file); // get the non-whitespace character
fscanf(file, " "); // skip whitespace
getc(file); // get the non-whitespace character

or

fscanf(file, " %c %c", &char1, &char2); // read 2 non-whitespace characters, skipping any whitespace before each

from:

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from the fscanf man page:

A directive is one of the following:
· A sequence of white-space characters (space, tab, newline, etc.;
see isspace(3)). This directive matches any amount of white
space, including none, in the input.

so

fscanf(file, " %s\n");


will skip all whitespace before reading in characters.

Your code is crashing because you have a `%s` in your format specifier in the `fscanf` call, and you don't pass `fscanf` a `char *` to which you want it to write the string it finds.

See

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.