+- 0Day Forums (https://zeroday.vip)
+-- Forum: Coding (https://zeroday.vip/Forum-Coding)
+--- Forum: Kotlin (https://zeroday.vip/Forum-Kotlin)
+--- Thread: Kotlin - KClass<*> from KType (/Thread-Kotlin-KClass-lt-gt-from-KType)
Kotlin - KClass<*> from KType - nonfrustration902665 - 07-20-2023
In Kotlin, I can obtain a `KType` from a `KClass<*>` like so:
Int::class.createType()
> kotlin.Int
How do I do the reverse and obtain the `KClass<Int>` from a `KType` representing a `kotlin.Int`?
RE: Kotlin - KClass<*> from KType - homotropal678503 - 07-20-2023
You can use [`KType.classifier`](
[To see links please register here]
) for this:val intType : KType = Int::class.createType()
val intClassifier : KClassifier? = intType.classifier
assertEquals(Int::class, intClassifier) // true
Note that since 1.3.40 you can also (at least on the JVM) use the experimental [`typeOf<Int>()`](
[To see links please register here]
) to get your [`KType`]([To see links please register here]
). You may want to have a look at the [1.3.40-announcement]([To see links please register here]
) to see whether that might be useful to you.Speaking of the JVM: on the JVM you can also use [`KType.jvmErasure`](
[To see links please register here]
) to get the actual class as also [marstran]([To see links please register here]
) pointed out in the comment.